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Structural dynamics and vibration testing

Energy lost in one sinusoidal damper cycle

Energy a linear viscous damper dissipates in one steady cycle of sinusoidal motion of peak displacement X at angular frequency ω.

Ref
SDY-04
Rev
v1
Field
Structural dynamics and vibration testing
Result
ΔE [J]

A linear viscous damper dissipates πcωX² in each cycle of steady sinusoidal motion of peak displacement X at angular frequency ω. The energy lost per cycle rises with the square of the amplitude and in direct proportion to the frequency. The same area equals the area of the force–displacement loop.

Energy a linear viscous damper dissipates in one steady cycle of sinusoidal motion of peak displacement X at angular frequency ω. It grows with the square of the amplitude.

Calculator

Solve for
J
N·s/m
1500
rad/s
1200
m
0.0010.05
  • Average power dissipated, cω²X²/21.6 W
  • Peak damper force, cωX16 N
  • Cycles per second, ω/2π3.183 Hz

What drives the result

Each variable is moved across its typical range while the others stay at the values above. The longest bar is the key driver.

Energy lost per cycle (J) current value 0.5027 J
XPeak displacementKey driver
0.0050312.6
ωForcing angular frequency
0.02515.03
cViscous damping coefficient
0.006283.14
  • The damper dissipates 0.5027 J per cycle, which at 3.18 cycles per second is an average of 1.6 W.
  • Doubling the amplitude quadruples the heat the damper must shed.
Chart data as tables

Ranked variables

VariableTypical rangeLowest resultHighest resultSwing (J)Local stepChange in result
X Peak displacement0.001 to 0.05 m0.00502712.5712.56+10%+21 %
ω Forcing angular frequency1 to 200 rad/s0.025135.0275.001+10%+10 %
c Viscous damping coefficient1 to 500 N·s/m0.0062833.1423.135+10%+10 %

Sweep of Peak displacement

Peak displacement (m)Energy lost per cycle (J)
0.0010.005027
0.0071250.2552
0.013250.8825
0.019381.887
0.02553.269
0.031635.027
0.037757.163
0.043889.676
0.0512.57

Sweep one variable

Energy lost per cycle (J)Hover, touch, or use the arrow keys on the chart
024681012 0.010.020.030.040.05 Peak displacement (m) now 0.5027

Variables and how each one contributes

ΔE

Energy lost per cycle

Result · J

What the equation gives you. Everything else feeds it.

c

Viscous damping coefficient

N·s/m · typical 1 to 500

The viscous damping coefficient, in N·s/m: the damper force per unit velocity. Raises the energy lost in direct proportion. Raising it by 10 % (to 88) moves the result by +10 %, from 0.5027 to 0.5529 J.

ω

Forcing angular frequency

rad/s · typical 1 to 200

The forcing angular frequency, in rad/s: the angular frequency of the steady sinusoidal motion. Raises the energy lost per cycle in direct proportion. Raising it by 10 % (to 22) moves the result by +10 %, from 0.5027 to 0.5529 J.

X

Peak displacement

m · typical 0.001 to 0.05

The peak displacement of the steady sinusoidal motion, in m. Raises the energy lost with the square of the amplitude. Raising it by 10 % (to 0.011) moves the result by +21 %, from 0.5027 to 0.6082 J.

Worked example with the values above

  1. Square the amplitude: X² = 1×10−4 m².
  2. Multiply by c and ω: 80 × 20 × 1×10−4 = 0.16.
  3. ΔE = π × that = 0.50265 J.

Assumptions and limits

  • A single, well-separated mode dominates the record and the damping is viscous (proportional to velocity) and light.
  • Peaks or half-power points are read from clean data with enough resolution.

Common mistakes

  • Mixing peak heights with peak-to-peak values, or taking peaks from opposite sides of the zero line.
  • Using a record that contains several modes, so the envelope is not a single exponential.
  • Using the half-power width when the frequency resolution is too coarse to resolve it.
  • Using an angular frequency in rad/s where Hz is expected, or the reverse.

Statistics and uncertainty

Decrements read from only one pair of peaks carry the reading error of both. Averaging over several cycles, or fitting an exponential to the whole envelope, cuts the scatter. Damping is itself an inexact, amplitude-dependent property, so quote the amplitude at which it was measured.

Where it is used

  • Identifying damping from an impact or ring-down test on a structure, instrument or component.
  • Setting the damping values used in finite-element and modal models.

Maths you need

  • Natural logarithm: the inverse of e to a power
  • Damping ratio: damping as a fraction of critical
  • Free decay: the envelope of an unforced vibration

Related formulas

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