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Library / Mechanical / MEC-29

Mechanical

Damping from a ring-down

Damping ratio from the decay of successive vibration peaks.

Ref
MEC-29
Rev
v1
Field
Mechanical
Result
ζ

Measure positive peak displacements from equilibrium, n full cycles apart. Applies to a free underdamped response dominated by one viscously damped mode.

The faster the peaks shrink in a ring-down, the more damping the system has.

Calculator

Solve for
mm
0.1100
mm
0.0150
120
  • Log decrement δ0.3054
  • Peak ratio per cycle1.357

What drives the result

Each variable is moved across its typical range while the others stay at the values above. The longest bar is the key driver.

Damping ratio () current value 0.04855
xi+nLater peakKey driver
−0.08510.344
xiStarting peak
−0.1920.168
nCycles between peaks
0.007290.144
  • For light damping ζ ≈ δ/(2π), so a 5% damping ratio shrinks each peak by about 27%.
  • Averaging over several cycles reduces the error from reading single peaks.
Chart data as tables

Ranked variables

VariableTypical rangeLowest resultHighest resultSwing ()Local stepChange in result
xi+n Later peak0.01 to 50 mm−0.085070.34410.4292+10%−10.4 %
xi Starting peak0.1 to 100 mm−0.19210.16830.3604+10%+10.4 %
n Cycles between peaks1 to 20 0.0072910.14430.137+10%−9.07 %

Sweep of Later peak

Later peak (mm)Damping ratio
0.010.3441
0.0290.2961
0.084090.2457
0.24380.1933
0.70710.1392
2.050.08377
5.9460.02757
17.24−0.02889
50−0.08507

Sweep one variable

Damping ratio ()Hover, touch, or use the arrow keys on the chart
−0.100.10.20.3 0.010.1110 Later peak (mm), log scale now 0.04855

Variables and how each one contributes

ζ

Damping ratio

Result ·

What the equation gives you. Everything else feeds it.

xi

Starting peak

mm · typical 0.1 to 100

Displacement of the first peak. Larger starting peaks mean more decay.

xi+n

Later peak

mm · typical 0.01 to 50

Displacement n cycles later. A smaller later peak means more damping.

n

Cycles between peaks

· typical 1 to 20

Number of full cycles. More cycles for the same ratio mean less damping per cycle.

Worked example with the values above

  1. δ = ln(10/4) / 3 = 0.3054.
  2. √(4π² + δ²) = 6.291.
  3. ζ = 0.3054 / 6.291 = 0.04855.

Assumptions and limits

  • Free underdamped response with viscous damping.
  • One dominant mode.

Common mistakes

  • Using the logarithm to base 10.
  • Measuring peak-to-peak instead of from equilibrium.

Statistics and uncertainty

A 2% error in reading each peak leads to about ±0.03 in δ over one cycle; measure over several cycles to reduce it.

Where it is used

  • Measuring damping from tap or snap tests.
  • Checking damper degradation.

Maths you need

  • Natural logarithm: ln
  • Free vibration: decaying oscillation

Related formulas

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