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Hydraulics, open channels and fluid power

Specific energy lost across a hydraulic jump

Energy per unit weight dissipated across a classical hydraulic jump in a rectangular channel, from the depths y₁ before and y₂ after it, with y₂ above y₁.

Ref
HYD-29
Rev
v1
Field
Hydraulics, open channels and fluid power
Result
ΔE [m]

Across a classical hydraulic jump in a rectangular channel the specific energy falls by ΔE = (y₂ − y₁)³/(4 y₁ y₂), where y₁ and y₂ are the depths before and after. The result is the energy dissipated per unit weight of liquid, in metres. It rises sharply with the depth ratio, so strong jumps dissipate most of the approaching energy. Use y₂ above y₁.

Energy per unit weight dissipated across a classical hydraulic jump in a rectangular channel, from the depths y₁ before and y₂ after it, with y₂ above y₁.

Calculator

Solve for
m
m
0.010.9
m
110
  • Depth ratio, y₂/y₁4
  • Upstream Froude number, √[(y₂/y₁)(y₂/y₁ + 1)/2]3.162
  • Energy loss as a share of the upstream depth, ΔE/y₁1.688

What drives the result

Each variable is moved across its typical range while the others stay at the values above. The longest bar is the key driver.

Energy loss (m) current value 0.4219 m
y2Depth after the jumpKey driver
92.7
y1Depth before the jump
2.78e-424.3
  • A jump from 0.25 m to 1 m loses 0.4219 m of head and corresponds to an upstream Froude number of 3.16.
  • Jumps with Fr₁ above about 4.5 are stable and efficient, dissipating more than half of the incoming energy.
Chart data as tables

Ranked variables

VariableTypical rangeLowest resultHighest resultSwing (m)Local stepChange in result
y2 Depth after the jump1 to 10 m0.421992.6992.26+10%+32.3 %
y1 Depth before the jump0.01 to 0.9 m2.778e-424.2624.26+10%−17.9 %

Sweep of Depth after the jump

Depth after the jump (m)Energy loss (m)
10.4219
2.1253.102
3.258.308
4.37516.04
5.526.31
6.62539.11
7.7554.44
8.87572.3
1092.69

Sweep one variable

Energy loss (m)Hover, touch, or use the arrow keys on the chart
020406080100 246810 Depth after the jump (m) now 0.4219

Variables and how each one contributes

ΔE

Energy loss

Result · m

What the equation gives you. Everything else feeds it.

y1

Depth before the jump

m · typical 0.01 to 0.9

The depth before the jump, in m. A larger y₁ reduces the depth ratio, so the energy loss changes. Raising it by 10 % (to 0.275) moves the result by −17.9 %, from 0.4219 to 0.3464 m.

y2

Depth after the jump

m · typical 1 to 10

The depth after the jump, in m. A larger y₂ raises the energy loss. Raising it by 10 % (to 1.1) moves the result by +32.3 %, from 0.4219 to 0.5583 m.

Worked example with the values above

  1. Depth change: y₂ − y₁ = 1 − 0.25 = 0.75 m; cubed 0.42188 m³.
  2. Denominator: 4 y₁ y₂ = 1 m².
  3. ΔE = 0.42188 m.

Assumptions and limits

  • A prismatic rectangular channel with hydrostatic pressure and a uniform velocity profile.
  • For jumps: a horizontal channel, negligible friction across the jump and momentum coefficient 1.

Common mistakes

  • Using total discharge where discharge per unit width is needed.
  • Applying the jump relation when Fr₁ is below 1, where no jump forms.
  • Measuring the energy from the wrong datum.

Statistics and uncertainty

Depths near the critical depth are very sensitive: a small change in energy gives a large change in depth. Jump relations are also sensitive to the upstream Froude number, so errors in the measured depth and discharge matter.

Where it is used

  • Locating control sections and finding whether flow is subcritical or supercritical.
  • Sizing stilling basins and tracing backwater and drawdown curves.

Maths you need

  • Froude number: Fr = V/√(g D), the ratio of flow speed to wave speed
  • Specific energy: energy per unit weight measured from the bed
  • Momentum conservation: force balance across the jump

Related formulas

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