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Solution chemistry, equilibria and kinetics

pH of an amphiprotic intermediate salt

Approximate pH of a solution of the intermediate salt HA⁻ of a diprotic acid H₂A, such as hydrogencarbonate.

Ref
SCH-14
Rev
v1
Field
Solution chemistry, equilibria and kinetics
Result
pH [pH]

The intermediate ion HA⁻ of a diprotic acid can both give and take a proton. When the acid steps are well separated, and the salt concentration is high, the pH is nearly the average of the two pKa values, pH ≈ ½(pKa1 + pKa2), independent of the concentration. It fails for very dilute solutions, where water matters, and for closely spaced pKa values, where the approximation breaks down.

Approximate pH of a solution of the intermediate salt HA⁻ of a diprotic acid H₂A, such as hydrogencarbonate. It is the average of the two pKa values and does not depend on the concentration.

Calculator

Solve for
pH
010
214
  • Hydronium concentration, 10^(−pH)1×10−6 mol/L
  • Gap between the pKa values4
  • pH if the second pKa rises by one unit6.5 pH

What drives the result

Each variable is moved across its typical range while the others stay at the values above. The longest bar is the key driver.

pH of the salt (pH) current value 6 pH
pKa2Second pKaKey driver
39
pKa1First pKa
49
  • With pKa values of 4 and 8 the intermediate salt has a pH near 6, whatever its concentration within the valid range.
  • This is how hydrogencarbonate (pKa 6.35 and 10.33) comes out near pH 8.3, the value used for the phenolphthalein endpoint.
Chart data as tables

Ranked variables

VariableTypical rangeLowest resultHighest resultSwing (pH)Local stepChange in result
pKa2 Second pKa2 to 14 396+10%+6.67 %
pKa1 First pKa0 to 10 495+10%+3.33 %

Sweep of Second pKa

Second pKapH of the salt (pH)
23
3.53.75
54.5
6.55.25
86
9.56.75
117.5
12.58.25
149

Sweep one variable

pH of the salt (pH)Hover, touch, or use the arrow keys on the chart
3456789 2468101214 Second pKa now 6

Variables and how each one contributes

pH

pH of the salt

Result · pH

What the equation gives you. Everything else feeds it.

pKa1

First pKa

· typical 0 to 10

The pKa of the first dissociation of H₂A. Raises the pH by half of its change. Raising it by 10 % (to 4.4) moves the result by +3.33 %, from 6 to 6.2 pH.

pKa2

Second pKa

· typical 2 to 14

The pKa of the second dissociation (of HA⁻). Raises the pH by half of its change. Raising it by 10 % (to 8.8) moves the result by +6.67 %, from 6 to 6.4 pH.

Worked example with the values above

  1. Add the pKa values: 4 + 8 = 12.
  2. Halve.
  3. pH ≈ 6.

Assumptions and limits

  • Dilute solutions in which concentrations stand for activities, with constants on the concentration scale.
  • No other acids, bases or dissolved gases such as CO₂ unless included.

Common mistakes

  • Using pKa where Ka is needed, or the reverse.
  • Using the Kw of 25 °C at other temperatures.
  • Ignoring water autoionisation for acids below about 10⁻⁶ M.

Statistics and uncertainty

Acid constants change with ionic strength and temperature, so results are best to about 0.05 pH units even with accurate constants. Calibration of a pH electrode contributes about 0.02 pH.

Where it is used

  • Calculating pH of dilute acids, salts and intermediate ions.
  • Finding which species dominates at a given pH.

Maths you need

  • pH: pH = −log₁₀ [H⁺]
  • Acid dissociation constant: Ka = [H⁺][A⁻]/[HA]
  • Water ion product: Kw = [H⁺][OH⁻]

Related formulas

Practise this formula