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Library / Foundations: Chemistry / FCH-29

Foundations: Chemistry

Hydrogen-ion concentration of a weak acid without the approximation

Exact hydrogen-ion concentration of a weak acid that dissociates only partly, from solving the quadratic instead of assuming the dissociation is small.

Ref
FCH-29
Rev
v1
Field
Foundations: Chemistry
Result
[H⁺] [mol/dm³]

For a weak monoprotic acid HA with dissociation constant Ka and initial concentration c₀, equilibrium needs [H⁺]²/(c₀ − [H⁺]) = Ka. Solving the quadratic exactly gives [H⁺] = (−Ka + √(Ka² + 4Kac₀))/2. The second form on the page is algebraically the same and avoids cancellation errors when Ka is tiny. It improves on the shortcut [H⁺] ≈ √(Kac₀), which fails when the acid is more than a few per cent dissociated.

Exact hydrogen-ion concentration of a weak acid that dissociates only partly, from solving the quadratic instead of assuming the dissociation is small. The second form avoids losing accuracy when Ka is very small.

Calculator

Solve for
mol/dm³
mol/dm³
1e-100.1
mol/dm³
1e-45
  • pH, −log₁₀[H⁺]3.002
  • Approximation √(Kac₀)0.001 mol/dm³
  • Error of the approximation relative to the exact value0.5012 %
  • Fraction dissociated, [H⁺]/c₀0.995 %

What drives the result

Each variable is moved across its typical range while the others stay at the values above. The longest bar is the key driver.

Hydrogen-ion concentration (mol/dm³) current value 9.95e-4 mol/dm³
KaAcid dissociation constantKey driver
3.16e-60.0618
c0Initial concentration of the acid
2.7e-50.00707
  • For Ka = 1×10−5 and c₀ = 0.1 mol/dm³ the exact [H⁺] is 9.95×10−4 mol/dm³ (pH 3.002). The shortcut √(Kac₀) = 0.001 is about 0.501 % too high.
  • Make the acid more dilute or stronger and the approximation worsens: the exact formula is needed once more than about 5 % of the acid has dissociated.
Chart data as tables

Ranked variables

VariableTypical rangeLowest resultHighest resultSwing (mol/dm³)Local stepChange in result
Ka Acid dissociation constant1e-10 to 0.1 mol/dm³3.162e-60.06180.0618+10%+4.86 %
c0 Initial concentration of the acid1e-4 to 5 mol/dm³2.702e-50.0070660.007039+10%+4.91 %

Sweep of Initial concentration of the acid

Initial concentration of the acid (mol/dm³)Hydrogen-ion concentration (mol/dm³)
1e-42.702e-5
3.867e-45.739e-5
0.0014951.174e-4
0.0057822.355e-4
0.022364.679e-4
0.086479.249e-4
0.33440.001824
1.2930.003591
50.007066

Sweep one variable

Hydrogen-ion concentration (mol/dm³)Hover, touch, or use the arrow keys on the chart
00.0020.0040.006 1e−40.0010.010.11 Initial concentration of the acid (mol/dm³), log scale now 9.95e-4

Variables and how each one contributes

[H⁺]

Hydrogen-ion concentration

Result · mol/dm³

What the equation gives you. Everything else feeds it.

Ka

Acid dissociation constant

mol/dm³ · typical 1e-10 to 0.1

The acid dissociation constant, in mol/dm³. For ethanoic acid it is about 1.8 × 10⁻⁵. The slider is logarithmic. Raises [H⁺] roughly with the square root of Ka for a weak acid, so a stronger acid gives more hydrogen ions. Raising it by 1×10−5 (to 2×10−5) moves the result by +41.1 %, from 9.95×10−4 to 0.001404 mol/dm³.

c0

Initial concentration of the acid

mol/dm³ · typical 1e-4 to 5

The initial concentration of the acid, in mol/dm³. The slider is logarithmic. Raises [H⁺] roughly with the square root of the concentration; a more dilute acid is a larger fraction dissociated but has fewer ions. Raising it by 0.1 (to 0.2) moves the result by +41.6 %, from 9.95×10−4 to 0.001409 mol/dm³.

Worked example with the values above

  1. Discriminant: Ka² + 4Kac₀ = 1×10−10 + 4×10−6 = 4×10−6; its square root is 0.002.
  2. Using the stable form: denominator Ka + √ = 0.00201; numerator 2Kac₀ = 2×10−6.
  3. [H⁺] = 2×10−6 / 0.00201 = 9.95×10−4 mol/dm³, a pH of 3.002.

Assumptions and limits

  • A monoprotic weak acid, with the auto-ionisation of water neglected (valid when [H⁺] is well above 10⁻⁶ mol/dm³).
  • Concentrations used in place of activities, which is acceptable for dilute solutions.

Common mistakes

  • Using the shortcut √(Kac₀) for a dilute or fairly strong acid.
  • Using the formula for a polyprotic acid, which needs each step treated separately.
  • Entering pKa where Ka is required.

Statistics and uncertainty

The pH depends on the logarithm of [H⁺], so a 10 % error in Ka shifts the pH by about 0.02 for a weak acid. Published Ka values depend on temperature and ionic strength, which dominates the uncertainty.

Where it is used

  • pH of a weak acid solution, such as a cleaning agent or a chemical reagent.
  • Checking how much error the common shortcut introduces.

Maths you need

  • Acid dissociation constant: ratio of products to the undissociated acid at equilibrium
  • Quadratic formula: solution of ax² + bx + c = 0

Related formulas

Practise this formula