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Circuits, electronics and noise

Hybrid-pi base input resistance

Small-signal resistance looking into the intrinsic base of a transistor with the emitter at AC ground, from the small-signal current gain and the transconductance.

Ref
ELN-19
Rev
v1
Field
Circuits, electronics and noise
Result
r_π [Ω]

In the hybrid-pi model the base current is gm·vbe/β, so the small-signal resistance looking into the intrinsic base is rπ = vbe/ib = β/gm. It is large for a low bias current and falls as the current rises. External bias resistors and the base spreading resistance come in parallel or series with it and are not included.

Small-signal resistance looking into the intrinsic base of a transistor with the emitter at AC ground, from the small-signal current gain and the transconductance. External bias resistors are not included.

Calculator

Solve for
Ω
20500
S
0.0010.4
  • Base current per collector current, 1/β0.008333
  • Base current at 1 mA collector current, 1 mA/β8.333×10−6 A
  • Input resistance with Re = 100 Ω unbypassed, rπ + (β + 1)·10015,100 Ω

What drives the result

Each variable is moved across its typical range while the others stay at the values above. The longest bar is the key driver.

Base input resistance (Ω) current value 3,000 Ω
gmTransconductanceKey driver
300120,000
βSmall-signal current gain
50012,500
  • With β = 120 and gm = 0.04 S the base input resistance is 3,000 Ω.
  • Because gm rises with bias current, doubling the collector current halves rπ and doubles the load the stage puts on its source.
Chart data as tables

Ranked variables

VariableTypical rangeLowest resultHighest resultSwing (Ω)Local stepChange in result
gm Transconductance0.001 to 0.4 S300120,000119,700+10%−9.09 %
β Small-signal current gain20 to 500 50012,50012,000+10%+10 %

Sweep of Transconductance

Transconductance (S)Base input resistance (Ω)
0.001120,000
0.050882,359
0.10081,191
0.1506796.7
0.2005598.5
0.2504479.3
0.3003399.7
0.3501342.7
0.4300

Sweep one variable

Base input resistance (Ω)Hover, touch, or use the arrow keys on the chart
020k40k60k80k100k120k 0.050.150.250.35 Transconductance (S) now 3,000

Variables and how each one contributes

r_π

Base input resistance

Result · Ω

What the equation gives you. Everything else feeds it.

β

Small-signal current gain

· typical 20 to 500

The small-signal current gain β, no units. Raises rπ in direct proportion. Raising it by 10 % (to 132) moves the result by +10 %, from 3,000 to 3,300 Ω.

gm

Transconductance

S · typical 0.001 to 0.4

The transconductance, in S. A larger gm means more collector current for each base volt, so rπ falls in inverse proportion. Raising it by 10 % (to 0.044) moves the result by −9.09 %, from 3,000 to 2,727 Ω.

Worked example with the values above

  1. Ratio: β/gm = 120 / 0.04.
  2. That is 3,000 Ω.
  3. rπ = 3,000 Ω.

Assumptions and limits

  • An NPN transistor in the forward-active region, with a fixed base–emitter drop of about 0.7 V.
  • Midband small signals, an AC-grounded supply and negligible transistor output conductance.

Common mistakes

  • Forgetting to check that the collector–base junction is still reverse biased.
  • Using the DC current gain where the small-signal gain is needed, or the reverse.
  • Forgetting that an unbypassed emitter resistor adds (β + 1) times its value to the input resistance.

Statistics and uncertainty

Transistor current gain β varies by a factor of two or more between parts and with temperature, so a stable design depends on emitter feedback, not on β. Thermal voltage changes by about 0.33 % per kelvin.

Where it is used

  • Setting the operating point of transistor amplifiers and switches.
  • Estimating small-signal gain, input resistance and the effect of emitter degeneration.

Maths you need

  • Thevenin equivalent: a source and a resistance in series
  • Transistor current gain: β = Ic / Ib
  • Thermal voltage: kT/q, about 25 mV at room temperature

Related formulas

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