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Library / Automotive and vehicle dynamics / VEH-61

Automotive and vehicle dynamics

Temporal frequency of a spatial road wave

Frequency in cycles per second at which a vehicle meets a sinusoidal road profile of wavelength λ, travelling at constant speed U along the measured wheel path.

Ref
VEH-61
Rev
v1
Field
Automotive and vehicle dynamics
Result
f [Hz]

A vehicle at speed U passes a sinusoidal road of wavelength λ in a time λ/U, so the frequency it feels is f = U/λ. This links the road’s spatial content to the vehicle’s frequency range: at a given speed, short wavelengths drive wheel hop and long wavelengths drive body bounce. The relation is exact for constant speed along the profile.

Frequency in cycles per second at which a vehicle meets a sinusoidal road profile of wavelength λ, travelling at constant speed U along the measured wheel path.

Calculator

Solve for
Hz
m/s
060
m
0.1100
  • Speed in kilometres per hour54 km/h
  • Angular frequency, 2πf31.42 rad/s
  • Wavelength that excites a 12 Hz wheel-hop at this speed, U/121.25 m

What drives the result

Each variable is moved across its typical range while the others stay at the values above. The longest bar is the key driver.

Excitation frequency (Hz) current value 5 Hz
λRoad wavelengthKey driver
0.15150
UVehicle speed
020
  • A 3 m wave at 15 m/s excites the vehicle at 5 Hz.
  • At this speed, wheel-hop around 12 Hz is excited by wavelengths near 1.25 m, and body bounce near 1.2 Hz by waves near 12.5 m.
Chart data as tables

Ranked variables

VariableTypical rangeLowest resultHighest resultSwing (Hz)Local stepChange in result
λ Road wavelength0.1 to 100 m0.15150149.8+10%−9.09 %
U Vehicle speed0 to 60 m/s02020+10%+10 %

Sweep of Road wavelength

Road wavelength (m)Excitation frequency (Hz)
0.1150
0.237163.25
0.562326.67
1.33411.25
3.1624.743
7.4992
17.780.8435
42.170.3557
1000.15

Sweep one variable

Excitation frequency (Hz)Hover, touch, or use the arrow keys on the chart
050100150 0.10.521050 Road wavelength (m), log scale now 5

Variables and how each one contributes

f

Excitation frequency

Result · Hz

What the equation gives you. Everything else feeds it.

U

Vehicle speed

m/s · typical 0 to 60

The vehicle speed, in m/s. Raises the excitation frequency in direct proportion. Raising it by 10 % (to 16.5) moves the result by +10 %, from 5 to 5.5 Hz.

λ

Road wavelength

m · typical 0.1 to 100

The road wavelength, in m. A longer wavelength lowers the frequency in inverse proportion. Raising it by 10 % (to 3.3) moves the result by −9.09 %, from 5 to 4.545 Hz.

Worked example with the values above

  1. Speed: U = 15 m/s.
  2. Wavelength: λ = 3 m.
  3. f = U/λ = 15 / 3 = 5 Hz.

Assumptions and limits

  • Constant vehicle speed along a straight wheel path, and a stationary, zero-mean road profile.
  • One-sided PSDs, with spatial frequency in cycles per metre and temporal frequency in hertz.

Common mistakes

  • Mixing cycles per metre with radians per metre, which differ by 2π.
  • Mixing one-sided and two-sided spectra.
  • Applying a spectral relation outside the wavelength band over which the road was measured.

Statistics and uncertainty

Measured road PSDs scatter by a factor of two or more between road sections, and a power-law fit describes only a limited band. Treat spectral levels as indicative of a road class, not of a specific road.

Where it is used

  • Converting measured road roughness into inputs for ride simulations.
  • Predicting which road wavelengths excite body bounce, pitch and wheel hop.

Maths you need

  • Wavelength and frequency: f = U/λ
  • Power spectral density: variance per unit frequency
  • Parseval’s theorem: the area under the PSD equals the variance

Related formulas

Practise this formula