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Circuits, electronics and noise

RMS output of a half-wave rectifier

True RMS value of an unfiltered half-wave rectified sine, including its DC component, for an ideal diode and a resistive load.

Ref
ELN-12
Rev
v1
Field
Circuits, electronics and noise
Result
Vrms [V]

The RMS of a half-wave rectified sine, over the whole input cycle, is Vp/2. The squared signal has an average of Vp²/4: half of the Vp²/2 of a full sine, because half the time the output is zero. This is the true RMS including the DC part, and is what a resistive load sees as heating.

True RMS value of an unfiltered half-wave rectified sine, including its DC component, for an ideal diode and a resistive load. It is larger than the average because the wave peaks.

Calculator

Solve for
V
V
0.5500
  • Average value, Vp/π3.82 V
  • RMS of the full sine, Vp/√28.485 V
  • Form factor, RMS over average (π/2)1.571

What drives the result

Each variable is moved across its typical range while the others stay at the values above. The longest bar is the key driver.

RMS output voltage (V) current value 6 V
VpSine peak voltageKey driver
0.25250
  • A 12 V peak half-wave signal has an RMS of 6 V, so a resistive load dissipates 0.36 W per 100 Ω.
  • The RMS (6 V) is larger than the average (3.82 V), and the ratio of 1.571 is the form factor of this waveform.
Chart data as tables

Ranked variables

VariableTypical rangeLowest resultHighest resultSwing (V)Local stepChange in result
Vp Sine peak voltage0.5 to 500 V0.25250249.8+10%+10 %

Sweep of Sine peak voltage

Sine peak voltage (V)RMS output voltage (V)
0.50.25
1.1860.5928
2.8121.406
6.6683.334
15.817.906
37.4918.75
88.9144.46
210.8105.4
500250

Sweep one variable

RMS output voltage (V)Hover, touch, or use the arrow keys on the chart
050100150200250 110100 Sine peak voltage (V), log scale now 6

Variables and how each one contributes

Vrms

RMS output voltage

Result · V

What the equation gives you. Everything else feeds it.

Vp

Sine peak voltage

V · typical 0.5 to 500

The peak voltage of the sinusoidal source, in V. Scales the RMS value in direct proportion. Raising it by 10 % (to 13.2) moves the result by +10 %, from 6 to 6.6 V.

Worked example with the values above

  1. Square the peak: Vp² = 144.
  2. The mean square over a full cycle is Vp²/4 = 36 V².
  3. Vrms = √36 = 6 V.

Assumptions and limits

  • Ideal diodes with zero forward drop for the rectifier formulas, and a resistive load.
  • A sinusoidal supply and, for the ripple formula, a small ripple compared with the peak.

Common mistakes

  • Using the peak value where an RMS or average value is needed.
  • Forgetting that a full-wave rectifier recharges twice per supply cycle, so the ripple frequency is 2f.
  • Ignoring the minimum Zener current, or its power rating.

Statistics and uncertainty

Rectifier formulas assume an ideal diode, so a real diode drop of about 0.7 V lowers the results for small peaks. Zener results depend on the supply, the Zener voltage tolerance and the load current, so use worst cases.

Where it is used

  • Power supplies, battery chargers and meter circuits.
  • Simple voltage references and regulators for sensors and microcontroller inputs.

Maths you need

  • Average and RMS values: the mean and root-mean-square of a waveform
  • Diode: conducts in one direction
  • Capacitor discharge: ΔV = I Δt / C

Related formulas

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