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Library / Foundations: Physics / FPH-40

Foundations: Physics

Radioactive decay and half-life

Activity remaining after a given time from the half-life.

Ref
FPH-40
Rev
v1
Field
Foundations: Physics
Result
A [kBq]

λ is the decay constant in s⁻¹. Activity A is in Bq. Subtract background from measured count rates before comparing decay fractions. The calculator uses A = A₀ × 2^(−t/t½).

Radioactive material halves in activity every half-life, so activity falls fast at first and then slowly.

Calculator

Solve for
kBq
kBq
1100,000
h
0.11,000
h
0.5200
  • Decay constant λ0.1155 h⁻¹
  • Fraction remaining6.25 %

What drives the result

Each variable is moved across its typical range while the others stay at the values above. The longest bar is the key driver.

Activity remaining (kBq) current value 6.25 kBq
A₀Initial activityKey driver
0.06256,250
t½Half-life
5.66e-7198.4
tElapsed time
9.24e-994.4
  • After 10 half-lives less than 0.1% remains.
  • Decay is random for each nucleus but follows this smooth rule for large numbers of atoms.
Chart data as tables

Ranked variables

VariableTypical rangeLowest resultHighest resultSwing (kBq)Local stepChange in result
A₀ Initial activity1 to 100,000 kBq0.06256,2506,250+10%+10 %
t½ Half-life0.1 to 1,000 h5.66e-7198.3598.35+10%+28.7 %
t Elapsed time0.5 to 200 h9.24e-994.3994.39+10%−24.2 %

Sweep of Elapsed time

Elapsed time (h)Activity remaining (kBq)
0.594.39
1.05788.5
2.23677.23
4.72957.91
1031.5
21.158.69
44.720.5705
94.570.001799
2009.24e-9

Sweep one variable

Activity remaining (kBq)Hover, touch, or use the arrow keys on the chart
020406080100 110100 Elapsed time (h), log scale now 6.25

Variables and how each one contributes

A

Activity remaining

Result · kBq

What the equation gives you. Everything else feeds it.

A₀

Initial activity

kBq · typical 1 to 100,000

Activity at t = 0. Directly proportional.

t½

Half-life

h · typical 0.1 to 1,000

Time for the activity to halve. A longer half-life slows the decay.

t

Elapsed time

h · typical 0.5 to 200

Time since t = 0. Each half-life halves the activity.

Worked example with the values above

  1. Number of half-lives: t/t½ = 24 / 6 = 4.
  2. Remaining fraction: 2−4 = 0.0625.
  3. A = 100 × 0.0625 = 6.25 kBq.

Assumptions and limits

  • A single isotope with no daughter activity.
  • Background subtracted.

Common mistakes

  • Using minutes for t but hours for the half-life.
  • Subtracting instead of multiplying by 2^(−n).

Statistics and uncertainty

Radioactive counts follow Poisson statistics: a count of N has an uncertainty of about √N, so longer counting times improve accuracy.

Where it is used

  • Radiological safety and source storage.
  • Dating and tracer work.

Maths you need

  • Exponentials: e^(−x) and 2^(−n)
  • Half-life: time to halve

Related formulas

Practise this formula