Your Equation

Library / Solution chemistry, equilibria and kinetics / SCH-38

Solution chemistry, equilibria and kinetics

Pseudo-first-order rate constant

Effective first-order rate constant for the rate k[A][B]ᵐ when B is in large excess or buffered, so that its concentration stays constant.

Ref
SCH-38
Rev
v1
Field
Solution chemistry, equilibria and kinetics
Result
kobs [1/s]

When the rate is k[A][B]ᵐ and B is in large excess or buffered, its concentration stays almost constant, so A decays as a first-order process with kobs = k Bᵐ. Plot ln[A] against time to get kobs, then repeat at different B to find m and k. Check that B changes by less than about 5 % during the run, or the pseudo-first-order treatment fails.

Effective first-order rate constant for the rate k[A][B]ᵐ when B is in large excess or buffered, so that its concentration stays constant. Check that B changes little over the time window.

Calculator

Solve for
1/s
(L/mol)^m/s
1e-61,000,000
mol/L
1e-410
04
  • Half-life of A, ln 2/kobs13.86 s
  • Time for 90 % conversion, ln 10/kobs46.05 s
  • kobs if B is doubled, 2ᵐ kobs0.2 1/s

What drives the result

Each variable is moved across its typical range while the others stay at the values above. The longest bar is the key driver.

Pseudo-first-order constant (1/s) current value 0.05 1/s
kRate constantKey driver
2.5e-7250,000
BConcentration of the excess reactant
2e-920
mOrder in B
0.01250.2
  • With 0.5 mol/L of B the effective first-order constant is 0.05 1/s, a half-life of 13.86 s for A.
  • Doubling B would raise kobs by 4, which is how the order m is read from the slope of ln kobs against ln B.
Chart data as tables

Ranked variables

VariableTypical rangeLowest resultHighest resultSwing (1/s)Local stepChange in result
k Rate constant1e-6 to 1,000,000 (L/mol)^m/s2.5e-7250,000250,000+10%+10 %
B Concentration of the excess reactant1e-4 to 10 mol/L2e-92020+10%+21 %
m Order in B0 to 4 0.01250.20.1875+10%−12.9 %

Sweep of Concentration of the excess reactant

Concentration of the excess reactant (mol/L)Pseudo-first-order constant (1/s)
1e-42e-9
4.217e-43.557e-8
0.0017786.325e-7
0.0074991.125e-5
0.031622e-4
0.13340.003557
0.56230.06325
2.3711.125
1020

Sweep one variable

Pseudo-first-order constant (1/s)Hover, touch, or use the arrow keys on the chart
05101520 1e−40.0010.010.1110 Concentration of the excess reactant (mol/L), log scale now 0.05

Variables and how each one contributes

kobs

Pseudo-first-order constant

Result · 1/s

What the equation gives you. Everything else feeds it.

k

Rate constant

(L/mol)^m/s · typical 1e-6 to 1,000,000

The rate constant of the full rate law. Raises kobs in direct proportion. Raising it by 10 % (to 0.22) moves the result by +10 %, from 0.05 to 0.055 1/s.

B

Concentration of the excess reactant

mol/L · typical 1e-4 to 10

The concentration of the excess reactant, in mol/L. Raises kobs, with a power set by the order m. Raising it by 10 % (to 0.55) moves the result by +21 %, from 0.05 to 0.0605 1/s.

m

Order in B

· typical 0 to 4

The order in B. A higher order makes kobs more sensitive to B (and smaller if B is below 1 mol/L). Raising it by 10 % (to 2.2) moves the result by −12.9 %, from 0.05 to 0.04353 1/s.

Worked example with the values above

  1. Power of B: Bᵐ = 0.5^2 = 0.25.
  2. Multiply by k = 0.2.
  3. kobs = 0.05 1/s.

Assumptions and limits

  • Constant volume, a well-mixed closed batch at fixed temperature.
  • The simple rate law stated, with the same mechanism over the range studied.

Common mistakes

  • Using the wrong sign of the stoichiometric coefficient for reactants and products.
  • Forgetting that a pseudo-first-order constant includes the excess reactant’s concentration.
  • Using rates from different times in a method of initial rates.

Statistics and uncertainty

Rate constants are normally known to 5 % to 10 % and change by about 7 % per kelvin near room temperature for a typical activation energy, so temperature control matters.

Where it is used

  • Finding reaction orders and rate constants from experiments.
  • Predicting selectivity and relaxation to equilibrium.

Maths you need

  • Rate law: rate = k[A]^m[B]^n
  • Stoichiometric coefficient: ν, negative for reactants
  • First-order decay: c = c₀ e^(−kt)

Related formulas

Practise this formula