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Electrical

Half-power bandwidth of a series RLC circuit

Width of the frequency band, between the two half-power points of the current response, around the resonance of a series RLC circuit.

Ref
ELE-36
Rev
v1
Field
Electrical
Result
Δf [Hz]

A series RLC circuit has a resonance peak whose width between the half-power points (where the power is half its peak) is Δf = R/(2πL), or R/L in rad/s. It depends only on R and L, not on C. The quality factor is Q = f₀/Δf: a low resistance gives a narrow, sharp peak. The same R/L also sets the decay rate of the free response, with an envelope e−Rt/2L.

Width of the frequency band, between the two half-power points of the current response, around the resonance of a series RLC circuit. A smaller resistance gives a narrower, sharper resonance.

Calculator

Solve for
Hz
Ω
0.11,000
mH
0.11,000
  • Bandwidth in rad/s, R/L1,000 rad/s
  • Time constant of the free-response envelope, 2L/R2 ms
  • Resonant frequency that would give Q = 10 with this bandwidth1,592 Hz

What drives the result

Each variable is moved across its typical range while the others stay at the values above. The longest bar is the key driver.

Half-power bandwidth (Hz) current value 159.2 Hz
LInductanceKey driver
1.5915,900
RSeries resistance
1.5915,900
  • A circuit with 10 Ω and 10 mH has a half-power bandwidth of 159.2 Hz. If it resonates at 1,590 Hz, its Q is 10; at 159 Hz, Q = 1.
  • Free oscillations die away with a time constant 2L/R = 2 ms: a narrow bandwidth means the circuit rings for a long time after being excited.
Chart data as tables

Ranked variables

VariableTypical rangeLowest resultHighest resultSwing (Hz)Local stepChange in result
L Inductance0.1 to 1,000 mH1.59215,92015,910+10%−9.09 %
R Series resistance0.1 to 1,000 Ω1.59215,92015,910+10%+10 %

Sweep of Series resistance

Series resistance (Ω)Half-power bandwidth (Hz)
0.11.592
0.31625.033
115.92
3.16250.33
10159.2
31.62503.3
1001,592
316.25,033
1,00015,920

Sweep one variable

Half-power bandwidth (Hz)Hover, touch, or use the arrow keys on the chart
0500010k15k 0.11101001000 Series resistance (Ω), log scale now 159.2

Variables and how each one contributes

Δf

Half-power bandwidth

Result · Hz

What the equation gives you. Everything else feeds it.

R

Series resistance

Ω · typical 0.1 to 1,000

The total series resistance, in ohms, including the coil and source resistance. Raises the bandwidth in direct proportion: more resistance flattens the peak and widens it. Raising it by 1 Ω (to 11 Ω) moves the result by +10 %, from 159.2 to 175.1 Hz.

L

Inductance

mH · typical 0.1 to 1,000

The inductance, in mH. Lowers the bandwidth in inverse proportion: a larger inductance sharpens the resonance. Raising it by 2 mH (to 12 mH) moves the result by −16.7 %, from 159.2 to 132.6 Hz.

Worked example with the values above

  1. Inductance in henries: L = 10 mH = 0.01 H.
  2. Denominator: 2πL = 2π × 0.01 = 0.06283 H.
  3. Δf = 10 / 0.06283 = 159.2 Hz.

Assumptions and limits

  • A series RLC circuit with a high enough Q that the bandwidth formula holds (Q above about 3).
  • Frequency-independent resistance.

Common mistakes

  • Looking for a dependence on C: the bandwidth does not depend on it, only the centre frequency does.
  • Using the formula in a parallel circuit, where the bandwidth is 1/(2πRC).

Statistics and uncertainty

Both R and L carry tolerance, and R also includes the loss in the coil, which rises with frequency (skin effect) and temperature, so a measured bandwidth is usually wider than the nominal value. Measure Δf directly with a frequency sweep for a critical filter.

Where it is used

  • Selectivity of a tuned circuit or filter, and the bandwidth of a receiver stage.
  • Estimating how long a resonant circuit rings.

Maths you need

  • Resonance: the frequency where the reactances cancel
  • Half-power points: frequencies where the power falls to half its peak

Related formulas

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