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Hydraulics, open channels and fluid power

Euler head transferred by a pump impeller

Ideal head given to the fluid by an impeller, from the blade speeds U and tangential components Vθ of the absolute velocity at outlet (2) and inlet (1).

Ref
HYD-39
Rev
v1
Field
Hydraulics, open channels and fluid power
Result
HE [m]

Applying angular momentum to the flow through an impeller gives the ideal energy transfer per unit mass, U₂Vθ₂ − U₁Vθ₁, with U the blade speed and Vθ the tangential component of the absolute velocity. Dividing by g gives the Euler head HE. With no whirl at the inlet it reduces to U₂Vθ₂/g. The real head is lower, because of friction, slip and other losses in the machine.

Ideal head given to the fluid by an impeller, from the blade speeds U and tangential components Vθ of the absolute velocity at outlet (2) and inlet (1). Actual head is lower, because of losses.

Calculator

Solve for
m
m/s
1200
m/s
−50200
m/s
0200
m/s
−50200
m/s²
130
  • Outlet term, U₂Vθ₂/g24.46 m
  • Inlet term, U₁Vθ₁/g0.8155 m
  • Specific work, U₂Vθ₂ − U₁Vθ₁232 J/kg

What drives the result

Each variable is moved across its typical range while the others stay at the values above. The longest bar is the key driver.

Euler head (m) current value 23.65 m
Vθ2Outlet tangential velocity componentKey driver
−103407
U2Blade speed at the outlet
0.408244
gGravitational acceleration
7.73232
Vθ1Inlet tangential velocity component
−13965.2
U1Blade speed at the inlet
4.0824.5
  • The impeller gives each kilogram 232 J, an ideal head of 23.65 m.
  • Removing the inlet whirl (Vθ₁ = 0) would raise the head to 24.46 m, which is why pumps are designed for radial entry.
Chart data as tables

Ranked variables

VariableTypical rangeLowest resultHighest resultSwing (m)Local stepChange in result
Vθ2 Outlet tangential velocity component−50 to 200 m/s−102.8406.9509.7+5 m/s+43.1 %
U2 Blade speed at the outlet1 to 200 m/s0.4077243.8243.4+10%+10.3 %
g Gravitational acceleration1 to 30 m/s²7.733232224.3+10%−9.09 %
Vθ1 Inlet tangential velocity component−50 to 200 m/s−138.665.24203.9+5 m/s−17.2 %
U1 Blade speed at the inlet0 to 200 m/s4.07724.4620.39+10%−0.345 %

Sweep of Blade speed at the outlet

Blade speed at the outlet (m/s)Euler head (m)
10.4077
25.8830.84
50.7561.26
75.6391.69
100.5122.1
125.4152.5
150.3183
175.1213.4
200243.8

Sweep one variable

Euler head (m)Hover, touch, or use the arrow keys on the chart
050100150200250 50100150200 Blade speed at the outlet (m/s) now 23.65

Variables and how each one contributes

HE

Euler head

Result · m

What the equation gives you. Everything else feeds it.

U2

Blade speed at the outlet

m/s · typical 1 to 200

The blade speed at the outlet, in m/s. Raises the head, since it multiplies Vθ₂. Raising it by 10 % (to 22) moves the result by +10.3 %, from 23.65 to 26.1 m.

Vθ2

Outlet tangential velocity component

m/s · typical −50 to 200

The tangential component of the absolute velocity at the outlet, in m/s. Raises the head in direct proportion to U₂. Raising it by 10 % (to 13.2) moves the result by +10.3 %, from 23.65 to 26.1 m.

U1

Blade speed at the inlet

m/s · typical 0 to 200

The blade speed at the inlet, in m/s. Lowers the head, through the inlet term. Raising it by 10 % (to 8.8) moves the result by −0.345 %, from 23.65 to 23.57 m.

Vθ1

Inlet tangential velocity component

m/s · typical −50 to 200

The tangential component of the absolute velocity at the inlet, in m/s. Lowers the head, through the inlet term. Raising it by 10 % (to 1.1) moves the result by −0.345 %, from 23.65 to 23.57 m.

g

Gravitational acceleration

m/s² · typical 1 to 30

The gravitational acceleration, in m/s². Lowers the head in inverse proportion. Raising it by 10 % (to 10.79) moves the result by −9.09 %, from 23.65 to 21.5 m.

Worked example with the values above

  1. Outlet term: U₂Vθ₂ = 20 × 12 = 240 m²/s².
  2. Inlet term: U₁Vθ₁ = 8 × 1 = 8 m²/s².
  3. HE = (240 − 8) / 9.81 = 23.649 m.

Assumptions and limits

  • Steady incompressible flow with the pump curve and system curve both of quadratic form.
  • Ideal blade-guided flow for the velocity-triangle results, so the real head is lower.

Common mistakes

  • Using gauge pressure where absolute pressure is needed for NPSH.
  • Forgetting that pump curves in different units, such as litres per second, need converting to m³/s.
  • Adding the flows of parallel pumps at different heads.

Statistics and uncertainty

Pump curves are known only to within a few percent and wear them down in service, and available suction head changes with the level, temperature and flow, so use a safety margin on the requirement.

Where it is used

  • Choosing pumps and finding the duty point on a pipe system.
  • Checking cavitation margin and estimating head from impeller geometry.

Maths you need

  • Pump curve: head against flow for a pump at a fixed speed
  • System curve: head needed by the pipe system against flow
  • Velocity triangle: the vector diagram of blade and fluid velocities

Related formulas

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