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Library / Foundations: Maths / FMA-53

Foundations: Maths

Direct and inverse proportion

How a quantity changes when another is scaled, if y is proportional to a power of x.

Ref
FMA-53
Rev
v1
Field
Foundations: Maths
Result
y2

If y is proportional to a power of x, y = k xn, then scaling x by a factor multiplies y by that factor raised to n: y2 = y1(x2/x1)n. With n = 1 this is direct proportion; with n = −1, inverse proportion; with n = 2, an area-like square law. The constant k cancels, so it is not needed. Starting values and exponents must be nonzero and the powers real.

How a quantity changes when another is scaled, if y is proportional to a power of x. An exponent of 1 is direct proportion, −1 is inverse proportion and 2 is the square law.

Calculator

Solve for
0.11,000
0.1100
0.1100
−33
  • Scaling factor for x, x2/x11.5
  • Scaling factor for y, (x2/x1)n0.6667
  • Constant of proportionality k = y1/x1n24

What drives the result

Each variable is moved across its typical range while the others stay at the values above. The longest bar is the key driver.

New value of y () current value 8
y1Starting value of yKey driver
0.0667667
x1Starting value of x
0.4400
x2New value of x
0.24240
nExponent n (1 direct, −1 inverse)
3.5640.5
  • With n = −1, changing x from 2 to 3 (a factor of 1.5) changes y from 12 to 8.
  • Doubling x would multiply y by 2−1 = 0.5: direct proportion doubles y, inverse proportion halves it and a square law multiplies it by four.
Chart data as tables

Ranked variables

VariableTypical rangeLowest resultHighest resultSwing ()Local stepChange in result
y1 Starting value of y0.1 to 1,000 0.06667666.7666.6+10%+10 %
x1 Starting value of x0.1 to 100 0.4400399.6+10%+10 %
x2 New value of x0.1 to 100 0.24240239.8+10%−9.09 %
n Exponent n (1 direct, −1 inverse)−3 to 3 3.55640.536.94+0.12 +4.99 %

Sweep of New value of x

New value of xNew value of y
0.1240
0.2371101.2
0.562342.68
1.33418
3.1627.589
7.4993.2
17.781.35
42.170.5691
1000.24

Sweep one variable

New value of y ()Hover, touch, or use the arrow keys on the chart
050100150200250 0.10.521050 New value of x, log scale now 8

Variables and how each one contributes

y2

New value of y

Result ·

What the equation gives you. Everything else feeds it.

y1

Starting value of y

· typical 0.1 to 1,000

The starting value of y, in its own unit. It is multiplied by the scaling factor. Raises the new value in direct proportion, because y₂ is a multiple of y₁. Raising it by 1 (to 13) moves the result by +8.33 %, from 8 to 8.667.

x1

Starting value of x

· typical 0.1 to 100

The starting value of x, in any unit used consistently with x₂. It must be nonzero. Changes the new value through the ratio x₂/x₁: raising x₁ lowers the ratio, which lowers y₂ for a positive exponent and raises it for a negative one. Raising it by 0.5 (to 2.5) moves the result by +25 %, from 8 to 10.

x2

New value of x

· typical 0.1 to 100

The new value of x, in the same unit as x₁. Changes the new value through the ratio x₂/x₁: raising x₂ raises y₂ for a positive exponent and lowers it for a negative one. Raising it by 0.5 (to 3.5) moves the result by −14.3 %, from 8 to 6.857.

n

Exponent n (1 direct, −1 inverse)

· typical −3 to 3

The exponent n in y = kxn: 1 for direct proportion, −1 for inverse, 2 for a square law. Sharpens the dependence on x: for x₂ larger than x₁ a larger n gives a larger y₂, and for x₂ smaller than x₁ it gives a smaller one. Raising it by 0.25 (to −0.75) moves the result by +10.7 %, from 8 to 8.853.

Worked example with the values above

  1. Ratio of the new to the old x: x2/x1 = 3 / 2 = 1.5.
  2. Raise it to the power n = −1: 1.5−1 = 0.6667.
  3. y2 = 12 × 0.6667 = 8.

Assumptions and limits

  • y is exactly proportional to x raised to a constant power, with no added constant.
  • Values nonzero and the power defined (a negative x with a fractional power is not allowed).

Common mistakes

  • Using a straight proportion when the relationship is a square or inverse law.
  • Dividing the wrong way: for inverse proportion the new y is y₁ × (x₁/x₂), which is the n = −1 case.

Statistics and uncertainty

For a power law the relative error of y is |n| times the relative error of x: with n = 2 a 1 % error in x gives about 2 %, and with n = −1 about 1 % in the opposite sense. A larger exponent therefore makes the result more sensitive to the input.

Where it is used

  • Scaling a result when one quantity changes: how time changes with speed, how force changes with area, how stress changes with diameter.
  • Comparing similar designs at different sizes.

Maths you need

  • Ratio: one quantity divided by another
  • Powers: repeated multiplication

Related formulas

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