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Circuits, electronics and noise

Butterworth low-pass magnitude response

Magnitude response of an nth-order Butterworth low-pass filter with unity DC gain and a −3 dB frequency fc.

Ref
ELN-38
Rev
v1
Field
Circuits, electronics and noise
Result
|H| [V/V]

A Butterworth low-pass filter of order n has |H| = 1/√(1 + (f/fc)^(2n)). It is maximally flat in the passband and exactly −3 dB (0.707) at fc for every order. Above fc the response falls at 20n dB per decade, so a higher order gives a sharper cut. At f = fc/2 the gain is still very close to 1 for a high order.

Magnitude response of an nth-order Butterworth low-pass filter with unity DC gain and a −3 dB frequency fc. The response is 1/√2 at fc for every order, and falls faster for higher orders.

Calculator

Solve for
V/V
Hz
1100,000
Hz
10100,000
110
  • Gain in decibels−12.3 dB
  • Roll-off rate far above fc, 20n40 dB/decade
  • Gain at f = 2 fc0.2425 V/V

What drives the result

Each variable is moved across its typical range while the others stay at the values above. The longest bar is the key driver.

Gain magnitude (V/V) current value 0.2425 V/V
fcCutoff (−3 dB) frequencyKey driver
2.5e-51
fFrequency
1e-41
nFilter order
9.77e-40.447
  • At 2,000 Hz an order-2 filter with fc = 1,000 Hz has a gain of 0.2425, which is −12.3 dB.
  • At f = fc the gain is always 0.7071 (−3.01 dB) for every order; only the steepness around that point changes.
Chart data as tables

Ranked variables

VariableTypical rangeLowest resultHighest resultSwing (V/V)Local stepChange in result
fc Cutoff (−3 dB) frequency10 to 100,000 Hz2.5e-511+10%+19.4 %
f Frequency1 to 100,000 Hz1e-410.9999+10%−16.6 %
n Filter order1 to 10 9.766e-40.44720.4462+1 −48.9 %

Sweep of Filter order

Filter orderGain magnitude (V/V)
10.4472
2.1250.2235
3.250.1045
4.3750.04814
5.50.02209
6.6250.01013
7.750.004645
8.8750.00213
109.766e-4

Sweep one variable

Gain magnitude (V/V)Hover, touch, or use the arrow keys on the chart
00.10.20.30.4 246810 Filter order now 0.2425

Variables and how each one contributes

|H|

Gain magnitude

Result · V/V

What the equation gives you. Everything else feeds it.

f

Frequency

Hz · typical 1 to 100,000

The frequency at which the gain is wanted, in Hz. A higher frequency gives a lower gain. Raising it by 10 % (to 2,200) moves the result by −16.6 %, from 0.2425 to 0.2023 V/V.

fc

Cutoff (−3 dB) frequency

Hz · typical 10 to 100,000

The −3 dB cut-off frequency, in Hz. A higher cut-off raises the gain at a fixed frequency. Raising it by 10 % (to 1,100) moves the result by +19.4 %, from 0.2425 to 0.2895 V/V.

n

Filter order

· typical 1 to 10

The filter order, a whole number from 1 upward. A higher order sharpens the cut, so the gain above fc falls and the gain below fc rises. Raising it by 10 % (to 2.2) moves the result by −12.3 %, from 0.2425 to 0.2127 V/V.

Worked example with the values above

  1. Frequency ratio: f/fc = 2,000 / 1,000 = 2.
  2. Raise to 2n = 4: 16.
  3. |H| = 1/√(1 + 16) = 0.24254.

Assumptions and limits

  • Ideal amplifiers with enough bandwidth, and ideal resistors and capacitors.
  • A source with low output impedance and a load that is much larger than the filter’s output impedance.

Common mistakes

  • Treating f₀ as the −3 dB frequency when Q is not the Butterworth value.
  • Using angular frequency where frequency in hertz is needed, a factor of 2π.
  • Rounding the filter order down: the ceiling is needed.

Statistics and uncertainty

Component tolerance moves the cut-off frequency and the quality factor: 1 % parts give about 1 % in f₀ but can move Q a lot when the design sits near instability. Real amplifier gain-bandwidth limits the filter at high frequency.

Where it is used

  • Anti-alias and noise-reduction filters before an ADC.
  • Choosing order, cut-off and quality factor of analogue filters from a specification.

Maths you need

  • Transfer function: output over input as a function of frequency
  • Decibel: 20 log₁₀ of a voltage ratio
  • Quality factor: Q, how sharply a resonance peaks

Related formulas

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