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Library / Solution chemistry, equilibria and kinetics / SCH-17

Solution chemistry, equilibria and kinetics

Buffer pH after a strong-base addition

pH of a buffer after x moles of strong base are added, from the starting moles of acid nHA and conjugate base nA.

Ref
SCH-17
Rev
v1
Field
Solution chemistry, equilibria and kinetics
Result
pH [pH]

Strong base added to a buffer first reacts completely with HA, converting it to A⁻: nHA falls by x and nA rises by x. The new pH comes from the Henderson–Hasselbalch equation with the new amounts, pH = pKa + log₁₀[(nA + x)/(nHA − x)]. It needs 0 ≤ x < nHA, so that some acid remains, and both components in a common final volume.

pH of a buffer after x moles of strong base are added, from the starting moles of acid nHA and conjugate base nA. The base first converts HA to A⁻, then the new ratio sets the pH. Needs 0 ≤ x < nHA.

Calculator

Solve for
pH
014
mol
5e-41
mol
0.021
mol
00.019
  • Starting pH, before the addition4.523 pH
  • pH change caused by the addition0.4771 pH
  • Acid remaining, nHA − x0.02 mol

What drives the result

Each variable is moved across its typical range while the others stay at the values above. The longest bar is the key driver.

pH after addition (pH) current value 5 pH
pKapKa of the weak acidKey driver
9.64e-1714
nHAStarting amount of weak acid HA
3.315.3
nAStarting amount of conjugate base A⁻
4.726.7
xAmount of OH⁻ added
4.525.42
  • Adding 0.01 mol of base moves the pH from 4.523 to 5, a change of 0.477 units.
  • The same addition to unbuffered water of this size would raise the pH by several units, which shows what the buffer does.
Chart data as tables

Ranked variables

VariableTypical rangeLowest resultHighest resultSwing (pH)Local stepChange in result
pKa pKa of the weak acid0 to 14 9.643e-171414+10%+10 %
nHA Starting amount of weak acid HA0.02 to 1 mol3.3055.3011.996+10%−1.21 %
nA Starting amount of conjugate base A⁻5e-4 to 1 mol4.726.7031.983+10%+0.424 %
x Amount of OH⁻ added0 to 0.019 mol4.5235.4210.8981+10%+0.869 %

Sweep of Amount of OH⁻ added

Amount of OH⁻ added (mol)pH after addition (pH)
04.523
0.0023754.651
0.004754.767
0.0071254.874
0.00954.978
0.011885.082
0.014255.187
0.016635.299
0.0195.421

Sweep one variable

pH after addition (pH)Hover, touch, or use the arrow keys on the chart
4.64.855.25.4 00.0050.010.015 Amount of OH⁻ added (mol) now 5

Variables and how each one contributes

pH

pH after addition

Result · pH

What the equation gives you. Everything else feeds it.

pKa

pKa of the weak acid

· typical 0 to 14

The pKa of the weak acid. Raises the pH one for one. Raising it by 10 % (to 5.5) moves the result by +10 %, from 5 to 5.5 pH.

nA

Starting amount of conjugate base A⁻

mol · typical 5e-4 to 1

The starting amount of conjugate base, in mol. Raises the pH by increasing the base-to-acid ratio. Raising it by 10 % (to 0.011) moves the result by +0.424 %, from 5 to 5.021 pH.

nHA

Starting amount of weak acid HA

mol · typical 0.02 to 1

The starting amount of weak acid, in mol. More acid lowers the pH and gives more resistance to added base. Raising it by 10 % (to 0.033) moves the result by −1.21 %, from 5 to 4.939 pH.

x

Amount of OH⁻ added

mol · typical 0 to 0.019

The amount of strong base added, in mol. Raises the pH, slowly at first and steeply as the acid runs out. Raising it by 10 % (to 0.011) moves the result by +0.869 %, from 5 to 5.043 pH.

Worked example with the values above

  1. After reaction: nA + x = 0.01 + 0.01 = 0.02 mol; nHA − x = 0.03 − 0.01 = 0.02 mol.
  2. Log of the ratio: log₁₀(1) = 9.6433×10−17.
  3. pH = 5 + 9.6433×10−17 = 5.

Assumptions and limits

  • A monoprotic weak acid and its conjugate base, both at appreciable concentration, in dilute solution.
  • Constant volume, with concentration-based constants and negligible activity effects.

Common mistakes

  • Adding the strong acid or base to the wrong component.
  • Using a buffer more than about one pH unit from its pKa.
  • Forgetting that the buffer ratio is of amounts in the same final volume.

Statistics and uncertainty

Buffer pH shifts with temperature, ionic strength and dilution, typically by 0.01 to 0.05 pH units, and the pKa itself carries an uncertainty of about 0.02 to 0.05.

Where it is used

  • Preparing buffers and predicting their response to added acid or base.
  • Choosing an indicator for a given pH range.

Maths you need

  • Henderson–Hasselbalch equation: pH = pKa + log₁₀([A⁻]/[HA])
  • Conjugate pair: a weak acid and its base
  • Buffer capacity: the base needed per unit pH change

Related formulas

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