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Bending moment at a three-hinged arch section

Bending moment at a section of a three-hinged arch, equal to the moment M0 in the equivalent simply supported beam minus the moment of the inward thrust H about the section, where y is the height of the section above the support chord.

Ref
CIV-39
Rev
v1
Field
Civil
Result
M [N·m]

At any section of a three-hinged arch with vertical loads and supports at the same level, the bending moment is the beam moment minus the moment of the thrust: M = M0 − Hy. The thrust lowers the moment by an amount that grows with the height y of the arch axis. If the arch is shaped so that M = 0 everywhere, it carries load by axial force alone.

Bending moment at a section of a three-hinged arch, equal to the moment M0 in the equivalent simply supported beam minus the moment of the inward thrust H about the section, where y is the height of the section above the support chord. Equal-level supports and vertical loads only; sagging is positive.

Calculator

Solve for
N·m
N·m
05,000,000
N
1001,000,000
m
020
  • Moment relief from the thrust, H·y80,000 N·m
  • Fraction of the beam moment removed0.8421
  • Ordinate giving zero moment, M₀/H2.375 m

What drives the result

Each variable is moved across its typical range while the others stay at the values above. The longest bar is the key driver.

Arch bending moment (N·m) current value 15,000 N·m
M0Beam moment at the sectionKey driver
−80,0004,920,000
HHorizontal thrust
−1,910,00094,800
yArch ordinate above the chord
−705,00095,000
  • The thrust removes 84.21 % of the beam moment, leaving 15 kN·m at this section.
  • The moment would vanish if the arch axis were at y = 2.375 m here, which is the funicular shape for this load.
Chart data as tables

Ranked variables

VariableTypical rangeLowest resultHighest resultSwing (N·m)Local stepChange in result
M0 Beam moment at the section0 to 5,000,000 N·m−80,0004,920,0005,000,000+10%+63.3 %
H Horizontal thrust100 to 1,000,000 N−1,905,00094,8002,000,000+10%−53.3 %
y Arch ordinate above the chord0 to 20 m−705,00095,000800,000+10%−53.3 %

Sweep of Arch ordinate above the chord

Arch ordinate above the chord (m)Arch bending moment (N·m)
095,000
2.5−5,000
5−105,000
7.5−205,000
10−305,000
12.5−405,000
15−505,000
17.5−605,000
20−705,000

Sweep one variable

Arch bending moment (N·m)Hover, touch, or use the arrow keys on the chart
−600k−400k−200k0 05101520 Arch ordinate above the chord (m) now 15,000

Variables and how each one contributes

M

Arch bending moment

Result · N·m

What the equation gives you. Everything else feeds it.

M0

Beam moment at the section

N·m · typical 0 to 5,000,000

The bending moment at the section in the equivalent simply supported beam, in N·m. Raises the arch moment in direct proportion. Raising it by 10 % (to 104,500) moves the result by +63.3 %, from 15,000 to 24,500 N·m.

H

Horizontal thrust

N · typical 100 to 1,000,000

The horizontal thrust at the supports, in N. Reduces the moment in direct proportion to H. Raising it by 10 % (to 44,000) moves the result by −53.3 %, from 15,000 to 7,000 N·m.

y

Arch ordinate above the chord

m · typical 0 to 20

The height of the arch axis above the support chord at the section, in m. A higher axis gives the thrust a larger lever arm, reducing the moment. Raising it by 10 % (to 2.2) moves the result by −53.3 %, from 15,000 to 7,000 N·m.

Worked example with the values above

  1. Beam moment: M0 = 95,000 N·m.
  2. Thrust moment: H·y = 40,000 × 2 = 80,000 N·m.
  3. M = 95,000 − 80,000 = 15,000 N·m.

Assumptions and limits

  • Supports at the same level and vertical loads only, for arches and for cables.
  • A flexible cable with negligible bending stiffness and a load uniform along the horizontal span (parabola).

Common mistakes

  • Using the cable formulas for a cable under its own weight, which hangs as a catenary.
  • Using sag measured from the wrong reference line.
  • Forgetting the vertical component of tension at the supports.

Statistics and uncertainty

Cable tension is inversely proportional to sag, so the formulas are very sensitive to the measured sag: a 5 % error in sag gives a 5 % error in tension. Real cables also stretch and have some bending stiffness, which shifts results by a few per cent.

Where it is used

  • Sizing cables, anchors, abutments and ties.
  • Finding thrust and moments in three-hinged arches.

Maths you need

  • Funicular shape: the shape that carries load by axial force only
  • Three-hinge condition: the moment at the crown hinge is zero
  • Horizontal tension: the constant horizontal component along a loaded cable

Related formulas

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