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Automotive and vehicle dynamics

Axle roll stiffness from two wheel springs

Roll stiffness of an axle from two equal wheel rates kw acting at half the track t/2 each side, for small roll about the centreline.

Ref
VEH-54
Rev
v1
Field
Automotive and vehicle dynamics
Result
K_φ [N m/rad]

For small roll angle φ, the two wheels move in opposite directions by ±(t/2)φ, so each wheel spring gives a force kw(t/2)φ at a lever arm t/2. The resisting moment is kw·t²φ/2, which gives the spring roll stiffness Kφ = kw·t²/2 of the axle. It depends on the square of the track, so wide tracks are stiff in roll for the same wheel rate.

Roll stiffness of an axle from two equal wheel rates kw acting at half the track t/2 each side, for small roll about the centreline. Spring contribution only; add anti-roll bar stiffness separately.

Calculator

Solve for
N m/rad
N/m
1,000500,000
m
0.33
  • Roll stiffness per degree670.2 N m/deg
  • Roll moment at 2° of roll1,340 N m
  • Spring force change at each wheel per degree of roll418.9 N

What drives the result

Each variable is moved across its typical range while the others stay at the values above. The longest bar is the key driver.

Axle roll stiffness (N m/rad) current value 38,400 N m/rad
kwWheel rateKey driver
1,280640,000
tTrack width
1,350135,000
  • The axle springs alone give 38,400 N m/rad, which resists 670.2 N m per degree of roll.
  • Doubling the track would quadruple this, so roll stiffness is often added with an anti-roll bar rather than by stiffening the wheel springs and spoiling ride.
Chart data as tables

Ranked variables

VariableTypical rangeLowest resultHighest resultSwing (N m/rad)Local stepChange in result
kw Wheel rate1,000 to 500,000 N/m1,280640,000638,700+10%+10 %
t Track width0.3 to 3 m1,350135,000133,700+10%+21 %

Sweep of Wheel rate

Wheel rate (N/m)Axle roll stiffness (N m/rad)
1,0001,280
63,38081,120
125,800161,000
188,100240,800
250,500320,600
312,900400,500
375,300480,300
437,600560,200
500,000640,000

Sweep one variable

Axle roll stiffness (N m/rad)Hover, touch, or use the arrow keys on the chart
0100k200k300k400k500k600k 100k200k300k400k500k Wheel rate (N/m) now 38,400

Variables and how each one contributes

K_φ

Axle roll stiffness

Result · N m/rad

What the equation gives you. Everything else feeds it.

kw

Wheel rate

N/m · typical 1,000 to 500,000

The wheel rate of each wheel, in N/m. Raises the roll stiffness in direct proportion. Raising it by 10 % (to 33,000) moves the result by +10 %, from 38,400 to 42,240 N m/rad.

t

Track width

m · typical 0.3 to 3

The track width, in m. Raises the roll stiffness with its square. Raising it by 10 % (to 1.76) moves the result by +21 %, from 38,400 to 46,460 N m/rad.

Worked example with the values above

  1. Half track: t/2 = 0.8 m; t² = 2.56 m².
  2. Kφ = kw t²/2 = 30,000 × 2.56 / 2.
  3. Kφ = 38,400 N m/rad, or 670.21 N m/deg.

Assumptions and limits

  • A linear suspension with small motion about the design ride height and a constant motion ratio.
  • Rigid links and negligible bush compliance, and no preload or geometric stiffness unless stated.

Common mistakes

  • Forgetting to square the motion ratio.
  • Using the inverse motion ratio, wheel travel per spring travel, in place of spring travel per wheel travel.
  • Adding spring and anti-roll-bar stiffness at different points without converting them to the same reference.

Statistics and uncertainty

Spring rates and installation ratios are usually known to about 3 % to 5 %, but the motion ratio enters squared, so a 3 % error in it becomes about 6 % in wheel rate.

Where it is used

  • Converting spring and damper settings to wheel rate and wheel damping.
  • Setting roll stiffness and front-to-rear roll balance.

Maths you need

  • Motion ratio: spring travel per unit wheel travel
  • Series springs: 1/k = 1/k₁ + 1/k₂
  • Roll stiffness: roll moment per radian of roll

Related formulas

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